x/x^2-25-6/x^2-10+25

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Solution for x/x^2-25-6/x^2-10+25 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

x/(x^2)-(6/(x^2))-25-10+25 = 0

x/(x^2)-6*x^-2-25-10+25 = 0

x^-1-6*x^-2-10 = 0

t_1 = x^-1

1*t_1^1-6*t_1^2-10 = 0

t_1-6*t_1^2-10 = 0

DELTA = 1^2-(-10*(-6)*4)

DELTA = -239

DELTA < 0

x belongs to the empty set

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